题目内容:
设z=xcosy-2yex+2x,则
分别为( )。
A.Cosy+2yex+2xln2,xsiny-ex
B.Cosy-2yex-2xln2,xsiny+2ex
C.Cosy-2yex+2xln2,-xsiny-2ex
D.siny-2yex+2xln2,Cosy-2ex
参考答案:
答案解析:
设z=xcosy-2yex+2x,则
分别为( )。
A.Cosy+2yex+2xln2,xsiny-ex
B.Cosy-2yex-2xln2,xsiny+2ex
C.Cosy-2yex+2xln2,-xsiny-2ex
D.siny-2yex+2xln2,Cosy-2ex